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5x^2+46x-112=0
a = 5; b = 46; c = -112;
Δ = b2-4ac
Δ = 462-4·5·(-112)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-66}{2*5}=\frac{-112}{10} =-11+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+66}{2*5}=\frac{20}{10} =2 $
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